Display details of manager who manages more than 5 employees. empno FROM EMP AS e LEFT OUTER JOIN EMP AS m ON e.

Display details of manager who manages more than 5 employees MGR AND employee. 19. SELECT FIRST_NAME FROM EMPLOYEES WHERE EMPLOYEE_ID IN (SELECT MANAGER_ID FROM EMPLOYEES GROUP BY MANAGER_ID HAVING COUNT(*)>5) Display employee name, job title, start date, and end date of past jobs of all employees with commission percentage null. Dec 6, 2019 · (SELECT EMPLOYEE_ID FROM JOB_HISTORY WHERE JOB_ID='IT_PROG')) 237. i tried the below query SELECT * FROM EMPLOYEES WHERE (SELECT ename FROM EMP WHERE empno = mgr) There are no records in EMP that meet this criteria. person_name: The employee’s name. – Aug 9, 2013 · ID Employee ManagerID 1 A NULL 2 B 2 3 C 2 I want to write a query that returns all non related ManagerID's and ID's where ManagerID is equal to the ID. +-----+ | Employee | +-----+ | Joe | +-----+ By the way, this is my fifth Aug 31, 2019 · Display details of manager who manages more than 5 employees. Jul 7, 2014 · i want to display department_id's along with count,and count should be more than 5, and i want to have employees who are not hired in January. (Columns: first_name - Rows: 11) 16. 242. Display country name, city, and number of departments where department has more than 5 employees. Give each column an appropriate label. If you want to display names you can use join or nested sql queries using the retrieved manager id. Post the details of the table which contains manager name. EMPNO = employee. Create region table 16. I know we have to use the Count function but don't really know how to create the query. Create employees table. By selecting the rows where the employee’s salary is greater than the manager’s salary, we can identify employees who earn more than their managers. You can only get count of employees under each manager name. manager_id = T2. mgr and e. staff t2 where t1. Display employee name, job title, start date, and end date of past jobs of all employees with commission percentage null. mgr = m. I created a query that I get employees who earning more than THEIR managers: select a. empno=p. The query would have the following syntax: Apr 13, 2018 · If "There may be two managers with same name" then it is not possible to get "count of employees under each manager" with this table, because it doesn't give manager id for an employee. SELECT e. Apr 7, 2024 · Given the Employee table, write a SQL query that finds employees who earn more than their managers. SELECT DEPARTMENT_NAME, FIRST_NAME, SALARY FROM DEPARTMENTS D JOIN EMPLOYEES E ON (D. (SELECT MAX(SALARY) FROM EMPLOYEES WHERE DEPARTMENT_ID = OUTER. Display details of manager who manages more than 5 employees. – PART 1 (Oracle) 14. Return department_id. 64. Oct 25, 2015 · Display department name, manager name, and salary of the manager for all managers whose experience is more than 5 years. empno; Jan 30, 2012 · This query returns just one of the managers if there is a tie: SELECT T2. Ename as Employee, m. employee (employee-name, street, city) works (employee-name, company-name, salary) company (company-name, city) manages (employee-name, manager-name) what is the query of Find all employees who earn more than the average salary of all employees of their company from the scheema? Apr 13, 2021 · SELECT * FROM EMPLOYEES; Now to get the details of all the employees who are also managers, we make use of the EMPLOYEE_ID field and the MANAGER_ID, and we will find out the details of employees who are also managers. Jul 9, 2014 · The table schema which you specified contains only the manager_id. 2. To solve this problem, we need to find employees who earn a higher salary than their respective managers. Our task is to find employees who have been linked to more than one manager. Return manager name, department ID. SQL>select dname from dept where dname like 'S%' and loc like '%K'; 88) Display those employees whose manager name is JONES. ename from emp e,emp p where e. DEPARTMENT_ID) 241. Name from Employee a inner join Employee b on a. you will have a table with mapping for manager_id and manager_name,post the schema of that table. ename AS Manager, m. You need to self-join to get this relation. Display department name, manager name, and salary of the manager for all managers whose experience is more than 5 years. Let’s do this ‘warm-up’ exercise. MANAGER_ID) Jan 30, 2012 · This query returns the manager_id and manager_name of the manager with the maximal number of employees. Dec 20, 2024 · From the following table, write a SQL query to find the departments where any manager manages four or more employees. staff t1 where not exists ( select 1 from sales. SAL > manager. Display the departments into which no employee joined in last two years. SQL>select p. I have two tables employees and department. mgr; Im getting the employees with their corresponding manager's ID; Ford 7566 Scott 7566 Allen 7698 James 7698 Martin 7698 Turner 7698 Ward 7698 Miller 7782 Adams 7788 Blake 7839 Clark 7839 Jones 7839 Smith 7902 I'm trying to figure out a query which shows the names of the employees who worked in more than 2 departments along with their wage and contact details. * FROM your_table_name AS employee JOIN your_table_name AS manager ON manager. empno FROM EMP AS e LEFT OUTER JOIN EMP AS m ON e. 20. * from from sales. mgr as reports_to from EMPLOYEES e inner join Employees m on e. staff_id=t2. Aug 3, 2024 · Imagine you have a table called Employee_Manager with these columns: employee_id: A unique number for each employee. display employee details who are reporting to blake and have commission without using null or not null are earning more than any of the manager employees but Dec 20, 2024 · SQL SUBQUERIES Exercise, Practice and Solution: From the following table, write a SQL query to find those managers who supervise four or more employees. select distinct e. department: The department where the employee works. Display years in which more than 10 employees joined. Display job title and average salary for employees who did a job in the past. ename AS Employee, e. 238. mgr =m. Dec 20, 2024 · The said query in SQL that retrieves the name of the manager(s) from the employees table who have the highest number of direct reports, along with the number of employees reporting to them. Salary How I can modify this query for get more than ANY managers? Apr 25, 2021 · Display all the details of the employees whose commission is more than their salary and create additional column – “Salary_range” of employees that are Managers or Salesmen for their salary range in following groups “Less than 2000”, “Between 2000 and 5000” and “More than 5000”, for all other employees(not Manager and neither The very early SQL implementations lacked derived tables and HAVING was a workaround for one of its most obvious drawbacks (how to select on the result of a set function from the SELECT clause). Display the details of employees drawing the highest salary in the department. select t1. . It then groups the result by the emp_name of the manager and counts the number of employees reporting to each manager. 65. ManagerId = b. Count All Employees Under Each Manager. The trick is in the HAVING clause, which allows aggregates and counts over multiple rows. The result should look like this, ID Employee ManagerID 1 A NULL 2 B 2 In essence no managers can be managers of managers. MANAGER_ID=E. SELECT DISTINCT DEPARTMENT_ID FROM EMPLOYEES GROUP BY DEPARTMENT_ID, MANAGER_ID HAVING COUNT(EMPLOYEE_ID) > 5 Change salary of employee 115 to 8000 if the existing salary is less than 6000. name FROM ( SELECT manager_id FROM table1 WHERE manager_id IS NOT NULL GROUP BY manager_id ORDER BY count(*) DESC LIMIT 1 ) AS T1 JOIN table1 AS T2 ON T1. Apr 30, 2019 · I need to get Employees earning more than any managers. ename='JONES'; 89) Display those employees whose salary is more than 3000 after giving 20% increment. 66. empno, m. Nov 25, 2020 · Logic says whenever there’s a NOT NULL value in the column manager_id, that employee reports to a manager. 17. Id where a. SELECT manager_id,name, count(*) FROM table GROUP BY manager_id, name HAVING max(count(*)); Display departments where any manager is managing more than 5 employees. The query joins the employees table with itself using the manager_id column to match employees with their managers. Display details of departments managed by ‘Smith’. select * from employee where emp_id not in (select manager_id from employee where manager_id IS NOT NULL); or. Of course, it’s possible an employee could be a manager and also have someone above them in the hierarchy. (Columns: last_name, department_name-Rows: 44) 15. SAL The advantage of this approach is that we have to switch from Inner Join to Left Join, changes required to the query would be lesser. Both of these having the EmployeeName field. Salary > b. SELECT DEPARTMENT_ID,FIRST_NAME, SALARY FROM EMPLOYEES OUTER WHERE SALARY = 240. Display the details of departments in which the max salary is greater than May 24, 2023 · Employees Earning More Than Their Managers: Solution using SQL. Sample table: employees Dec 20, 2024 · The query joins the employees table with itself using the manager_id column to match employees with their managers. 239. 18. manager_id ) find more : Finding employees who are not managers Aug 1, 2019 · I have the following database scheema. Create a report for the HR department that displays employee last names, department numbers, and all the employees who work in the same department as a given employee. person_id Result of query: Bar Oct 10, 2022 · SELECT employee. For the above table, Joe is the only employee who earns more than his manager because Henry's Manager is Max, who earns 90000, which is more than Henry's salary of 80000. manager_id: A unique number for each manager. kqiiyzv hnxwagw ugtpb hmcw uahkp uipmlex qdenr ftm nynp dlbyw